Answer by Dan for Lorentz transformation of the vacuum state
As has been mentioned in the comments, it is an assumption that the QFT has a vacuum state which is annihilated by $P^\mu$. This is actually a very important point, since it is one of the crucial...
View ArticleLorentz transformation of the vacuum state
In general, the Hamiltonian $H$ has non-zero vacuum expectation value (VEV):$$ H \left.| \Omega \right> = E_0 \left.|\Omega \right>, $$ where $\left.|\Omega\right>$ is the vacuum state. The...
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